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1/3 y = sin ( 2x + π 3 ) = sin ( 2 ( x + π 6 )) 1 2 -→ y = sin 2x π 6

1/3 y = sin ( 2x + π 3 ) = sin ( 2 ( x + π 6 )) 1 2 -→ y = sin 2x π 6

1/2 I = 1 2 ∫ sin 2xdx = - 1 4 cos 2x + C1 = 1 - 2 cos x 4 + C1 =

1/2 I = 1 2 ∫ sin 2xdx = - 1 4 cos 2x + C1 = 1 - 2 cos x 4 + C1 =